Hello, I want to power my RAK board using a battery so that I can place it outside and collect UV-readings without having to connect the board to my Laptop. I need to do this for roughly an hour only.
I have two 1.5V AA batteries that I can combine to produce 3V. These batteries have a current-voltage-time graph of:
(So if my board draws less than 100mA then the batteries should last at 1.5V for close to an hour).
The RAK core only draws 3.35mA and the sensor only uses 110 microAmps so the batteries will be able to power the device. Also The RAK core operates on 2.0 - 3.6V and the sensor on 2.8V hence, the 3V should be enough.
I have a 5V adapter (it has a very long cord which allows me to place my device outside). The adaptor has a current output of 500mA. I am worried that this current will destroy the RAK base.
Can I connect my adaptor to the solar panel connector of the RAK base instead of the battery connector because the battery connector can only take 4.3V whilst the solar panel can take 5.5V.
Here is where I got the info from:
Is it true that the RAK base regulates the amount of voltage and current that the RAK core and RAK sensor receives. i.e. if I supply 3.7V and 1A of power to the board and the sensor only needs 2.8V and 0.3A, will my board step down the voltage and current to 2.8V and 0.3A?
RAK core: RAK 4630
RAK base: RAK 5005-O
RAK sensor: RAK 12019 UV sensor